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authorColin Ian King <colin.i.king@gmail.com>2025-05-07 11:43:37 +0100
committerDaniel Thompson (RISCstar) <danielt@kernel.org>2025-09-20 21:19:09 +0100
commitfdbdd0ccb30af18d3b29e714ac8d5ab6163279e0 (patch)
treea361b8499c5b00c8ad459bb0eac5709613e74857 /kernel
parent0c28a23722e03695ae1cbbadde3dd32d75c1cb7f (diff)
kdb: remove redundant check for scancode 0xe0
The check for scancode 0xe0 is always false because earlier on the scan code is masked with 0x7f so there are never going to be values greater than 0x7f. Remove the redundant check. Signed-off-by: Colin Ian King <colin.i.king@gmail.com> Reviewed-by: Douglas Anderson <dianders@chromium.org> Signed-off-by: Daniel Thompson (RISCstar) <danielt@kernel.org>
Diffstat (limited to 'kernel')
-rw-r--r--kernel/debug/kdb/kdb_keyboard.c3
1 files changed, 0 insertions, 3 deletions
diff --git a/kernel/debug/kdb/kdb_keyboard.c b/kernel/debug/kdb/kdb_keyboard.c
index 3a74604fdb8a..386d30e530b7 100644
--- a/kernel/debug/kdb/kdb_keyboard.c
+++ b/kernel/debug/kdb/kdb_keyboard.c
@@ -145,9 +145,6 @@ int kdb_get_kbd_char(void)
return CTRL('F');
}
- if (scancode == 0xe0)
- return -1;
-
/*
* For Japanese 86/106 keyboards
* See comment in drivers/char/pc_keyb.c.